我在Ubuntu 18.04上使用SBCL 1.4.5。
SBCL中的垃圾收集器似乎没有正确释放绑定到具有符号键和值的哈希表的内存。有趣的是,当键和值是整数时,垃圾收集工作得很好。
例如,以下程序可以正常运行:
(defun copy-hash-table (hash)
(let ((h (make-hash-table
:test (hash-table-test hash)
:rehash-size (hash-table-rehash-size hash)
:rehash-threshold (hash-table-rehash-threshold hash)
:size (hash-table-size hash))))
(loop for key being the hash-keys of hash
using (hash-value value)
do
(setf (gethash key h) value)
finally (return h))))
(defun make-integer-input ()
(loop
with hash1 = (make-hash-table) and hash2 = (make-hash-table)
for i from 0 to 500
do
(setf (gethash (random 100) hash1) (random 100))
(setf (gethash (random 100) hash2) (random 100))
finally
(return (list hash1 hash2))))
(defun do-integer-work (hash1 hash2)
(loop
for i being the hash-keys of hash1
for j being the hash-keys of hash2
do
(remhash i hash1)
(setf (gethash i hash1) (random 100))
(remhash j hash2)
(setf (gethash j hash2) (random 100)))
(values hash1 hash2))
(defun hash-worker (list-obj)
(loop
with next
for i from 1 to 50000
do
(multiple-value-bind (new-hash1 new-hash2)
(do-integer-work (copy-hash-table (first list-obj)) (copy-hash-table (second list-obj)))
(setq next (list new-hash1 new-hash2))
(if (> (random 100) 50)
(setq list-obj next)))))
我通过调用(hash-worker (make-integer-input))
来运行这个程序。顶级函数hash-worker
接受两个哈希表的列表,并在do-integer-work
中处理哈希表的副本。然后,帮助函数输出两个修改后的哈希表,它们分别保存在new-hash1
和new-hash2
中。然后系统随机决定是否保留修改后的哈希表。
do-integer-work
助手函数按顺序删除哈希表的键,并用新的随机值重新提交它们。
当这个程序运行时,我观察到在程序的持续时间内,内存消耗基本上是恒定的。当我在具有符号键和值的哈希表上运行姐妹程序时,情况并非如此。
(defun copy-hash-table (hash)
(let ((h (make-hash-table
:test (hash-table-test hash)
:rehash-size (hash-table-rehash-size hash)
:rehash-threshold (hash-table-rehash-threshold hash)
:size (hash-table-size hash))))
(loop for key being the hash-keys of hash
using (hash-value value)
do
(setf (gethash key h) value)
finally (return h))))
(defun make-symbol-input ()
(loop
with hash1 = (make-hash-table) and hash2 = (make-hash-table)
for i from 0 to 500
do
(setf (gethash (gentemp) hash1) (gentemp))
(setf (gethash (gentemp) hash2) (gentemp))
finally
(return (list hash1 hash2))))
(defun do-symbol-work (hash1 hash2)
(loop
for i being the hash-keys of hash1
for j being the hash-keys of hash2
do
(remhash i hash1)
(setf (gethash i hash1) (gentemp))
(remhash j hash2)
(setf (gethash j hash2) (gentemp)))
(values hash1 hash2))
(defun hash-worker (list-obj)
(loop
with next
for i from 1 to 50000
do
(multiple-value-bind (new-hash1 new-hash2)
(do-symbol-work (copy-hash-table (first list-obj)) (copy-hash-table (second list-obj)))
(setq next (list new-hash1 new-hash2))
(if (> (random 100) 50)
(setq list-obj next)))))
我运行了一个名为(hash-worker (make-symbol-input))
的程序。这个程序的不同之处在于,顶级函数调用do-symbol-work
。当这个程序运行时,我观察到系统的内存使用量稳步增加,直到我的机器耗尽内存。
这是SBCL中的已知错误吗?如果是,是否有解决方法?
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